Draw the structure of the neutral product formed in the following reaction.
Concepts and reason
Michael Reaction
The Michael reaction or Michael addition is the organic reaction in which a carbanion as in the form of an enolate ion adds to an
Fundamentals
Michael reaction:
Answer:
Deprotonation Step
It is an acid-base reaction. An ethoxide ion is a strong base and deprotonate the acidic alpha hydrogen present in the diketone (Michael donor) forming the carbanion which is stabilized by the resonance, giving the most stable enolate ion because the oxygen atom is more electronegative than the carbon atom.
1,4-Addition Step
The nucleophilic carbanion (enolate) attacks the carbon-carbon double bond present in the
Answer :-
Protonation Step
Again, it is an acid-base reaction. The intermediate enolate ion is a strong base that can abstract a proton from ethanol, regenerating the ethoxide base back and gives the more stable thermodynamic product as the Michael adduct.
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Question “Draw the structure of the neutral product formed in the following reaction. Draw the structure of…”
Draw the structure of the neutral product formed in the
following reaction.
Draw the structure of the neutral product formed in the following reaction
Answer
Michael Reaction
The Michael reaction, also known as Michael addition, is an organic reaction where a carbanion, in the form an enolate, adds to an
via conjugated adding. This results in the formation a new carbon-carbon single bonds between the Michael donor, and the Michael acceptor, creating the Michael adduct.
Michael reaction:
Ans:
Conclusion
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